2(t-5)=48

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Solution for 2(t-5)=48 equation: 



2(t-5)=48

We move all terms to the left:

2(t-5)-(48)=0

We multiply parentheses

2t-10-48=0

We add all the numbers together, and all the variables

2t-58=0

We move all terms containing t to the left, all other terms to the right

2t=58

t=58/2

t=29

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