2(t-5)+8=5(2t+5)-13

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Solution for 2(t-5)+8=5(2t+5)-13 equation: 



2(t-5)+8=5(2t+5)-13

We move all terms to the left:

2(t-5)+8-(5(2t+5)-13)=0

We multiply parentheses

2t-(5(2t+5)-13)-10+8=0



We calculate terms in parentheses: -(5(2t+5)-13), so:

5(2t+5)-13

We multiply parentheses

10t+25-13

We add all the numbers together, and all the variables

10t+12

Back to the equation:

-(10t+12)



We add all the numbers together, and all the variables

2t-(10t+12)-2=0

We get rid of parentheses

2t-10t-12-2=0

We add all the numbers together, and all the variables

-8t-14=0

We move all terms containing t to the left, all other terms to the right

-8t=14

t=14/-8

t=-1+3/4

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