12(r-3)=6(r+3)=

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Solution for 12(r-3)=6(r+3)= equation:



12(r-3)=6(r+3)=
We move all terms to the left:
12(r-3)-(6(r+3))=0
We multiply parentheses
12r-(6(r+3))-36=0
We calculate terms in parentheses: -(6(r+3)), so:
6(r+3)
We multiply parentheses
6r+18
Back to the equation:
-(6r+18)
We get rid of parentheses
12r-6r-18-36=0
We add all the numbers together, and all the variables
6r-54=0
We move all terms containing r to the left, all other terms to the right
6r=54
r=54/6
r=9

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