2(t-4)+6=2-4(2t-1)+6t

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Solution for 2(t-4)+6=2-4(2t-1)+6t equation: 



2(t-4)+6=2-4(2t-1)+6t

We move all terms to the left:

2(t-4)+6-(2-4(2t-1)+6t)=0

We multiply parentheses

2t-(2-4(2t-1)+6t)-8+6=0



We calculate terms in parentheses: -(2-4(2t-1)+6t), so:

2-4(2t-1)+6t

determiningTheFunctionDomain
-4(2t-1)+6t+2

We add all the numbers together, and all the variables

6t-4(2t-1)+2

We multiply parentheses

6t-8t+4+2

We add all the numbers together, and all the variables

-2t+6

Back to the equation:

-(-2t+6)



We add all the numbers together, and all the variables

2t-(-2t+6)-2=0

We get rid of parentheses

2t+2t-6-2=0

We add all the numbers together, and all the variables

4t-8=0

We move all terms containing t to the left, all other terms to the right

4t=8

t=8/4

t=2

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