1/2(12+576)=6/5(25x+50)

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Solution for 1/2(12+576)=6/5(25x+50) equation:



1/2(12+576)=6/5(25x+50)
We move all terms to the left:
1/2(12+576)-(6/5(25x+50))=0
Domain of the equation: 5(25x+50))!=0
x∈R
We add all the numbers together, and all the variables
-(6/5(25x+50))+1/2588=0
We calculate fractions
()/323500x+(5x2/323500x=0
We multiply all the terms by the denominator
(5x2+()=0
We calculate terms in parentheses: +(5x2+(), so:
5x2+(
We add all the numbers together, and all the variables
5x^2
Back to the equation:
+(5x^2)
a = 5; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·5·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{10}=0$

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