2(t-2)-3(4t-3)=11-5(6t+5)

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Solution for 2(t-2)-3(4t-3)=11-5(6t+5) equation: 



2(t-2)-3(4t-3)=11-5(6t+5)

We move all terms to the left:

2(t-2)-3(4t-3)-(11-5(6t+5))=0

We multiply parentheses

2t-12t-(11-5(6t+5))-4+9=0



We calculate terms in parentheses: -(11-5(6t+5)), so:

11-5(6t+5)

determiningTheFunctionDomain
-5(6t+5)+11

We multiply parentheses

-30t-25+11

We add all the numbers together, and all the variables

-30t-14

Back to the equation:

-(-30t-14)



We add all the numbers together, and all the variables

-10t-(-30t-14)+5=0

We get rid of parentheses

-10t+30t+14+5=0

We add all the numbers together, and all the variables

20t+19=0

We move all terms containing t to the left, all other terms to the right

20t=-19

t=-19/20

t=-19/20

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