4(z+4)=3(z-7)+z

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Solution for 4(z+4)=3(z-7)+z equation: 



4(z+4)=3(z-7)+z

We move all terms to the left:

4(z+4)-(3(z-7)+z)=0

We multiply parentheses

4z-(3(z-7)+z)+16=0



We calculate terms in parentheses: -(3(z-7)+z), so:

3(z-7)+z

We add all the numbers together, and all the variables

z+3(z-7)

We multiply parentheses

z+3z-21

We add all the numbers together, and all the variables

4z-21

Back to the equation:

-(4z-21)



We get rid of parentheses

4z-4z+21+16=0

We add all the numbers together, and all the variables

37!=0

There is no solution for this equation

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