2(t+2)=4(t-2)

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Solution for 2(t+2)=4(t-2) equation: 



2(t+2)=4(t-2)

We move all terms to the left:

2(t+2)-(4(t-2))=0

We multiply parentheses

2t-(4(t-2))+4=0



We calculate terms in parentheses: -(4(t-2)), so:

4(t-2)

We multiply parentheses

4t-8

Back to the equation:

-(4t-8)



We get rid of parentheses

2t-4t+8+4=0

We add all the numbers together, and all the variables

-2t+12=0

We move all terms containing t to the left, all other terms to the right

-2t=-12

t=-12/-2

t=+6

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