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x*1.3x=1933
We move all terms to the left:
x*1.3x-(1933)=0
Wy multiply elements
x^2-1933=0
a = 1; b = 0; c = -1933;
Δ = b2-4ac
Δ = 02-4·1·(-1933)
Δ = 7732
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{7732}=\sqrt{4*1933}=\sqrt{4}*\sqrt{1933}=2\sqrt{1933}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{1933}}{2*1}=\frac{0-2\sqrt{1933}}{2} =-\frac{2\sqrt{1933}}{2} =-\sqrt{1933} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{1933}}{2*1}=\frac{0+2\sqrt{1933}}{2} =\frac{2\sqrt{1933}}{2} =\sqrt{1933} $
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