2(s+5)=2-4(2s-2)+9s

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Solution for 2(s+5)=2-4(2s-2)+9s equation: 



2(s+5)=2-4(2s-2)+9s

We move all terms to the left:

2(s+5)-(2-4(2s-2)+9s)=0

We multiply parentheses

2s-(2-4(2s-2)+9s)+10=0



We calculate terms in parentheses: -(2-4(2s-2)+9s), so:

2-4(2s-2)+9s

determiningTheFunctionDomain
-4(2s-2)+9s+2

We add all the numbers together, and all the variables

9s-4(2s-2)+2

We multiply parentheses

9s-8s+8+2

We add all the numbers together, and all the variables

s+10

Back to the equation:

-(s+10)



We get rid of parentheses

2s-s-10+10=0

We add all the numbers together, and all the variables

s=0

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