(2x+1)(2-x)=0

Solution for (2x+1)(2-x)=0 equation:

(2x+1)(2-x)=0

We add all the numbers together, and all the variables

(2x+1)(-1x+2)=0

We multiply parentheses ..

(-2x^2+4x-1x+2)=0

We get rid of parentheses

-2x^2+4x-1x+2=0

We add all the numbers together, and all the variables

-2x^2+3x+2=0

a = -2; b = 3; c = +2;
Δ = b2-4ac
Δ = 32-4·(-2)·2
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-5}{2*-2}=\frac{-8}{-4}
=+2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+5}{2*-2}=\frac{2}{-4}
=-1/2
$