2(s+5)-7=3(s-2)

Solution for 2(s+5)-7=3(s-2) equation:

2(s+5)-7=3(s-2)

We move all terms to the left:

2(s+5)-7-(3(s-2))=0

We multiply parentheses

2s-(3(s-2))+10-7=0


We calculate terms in parentheses: -(3(s-2)), so:

3(s-2)

We multiply parentheses

3s-6

Back to the equation:

-(3s-6)


We add all the numbers together, and all the variables

2s-(3s-6)+3=0

We get rid of parentheses

2s-3s+6+3=0

We add all the numbers together, and all the variables

-1s+9=0

We move all terms containing s to the left, all other terms to the right

-s=-9

s=-9/-1

s=+9