4z-1=4(z+3)

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Solution for 4z-1=4(z+3) equation: 



4z-1=4(z+3)

We move all terms to the left:

4z-1-(4(z+3))=0



We calculate terms in parentheses: -(4(z+3)), so:

4(z+3)

We multiply parentheses

4z+12

Back to the equation:

-(4z+12)



We get rid of parentheses

4z-4z-12-1=0

We add all the numbers together, and all the variables

-13!=0

There is no solution for this equation

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