2(r+4)+6=-(1-2r)+3r

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Solution for 2(r+4)+6=-(1-2r)+3r equation: 



2(r+4)+6=-(1-2r)+3r

We move all terms to the left:

2(r+4)+6-(-(1-2r)+3r)=0

We add all the numbers together, and all the variables

2(r+4)-(-(-2r+1)+3r)+6=0

We multiply parentheses

2r-(-(-2r+1)+3r)+8+6=0



We calculate terms in parentheses: -(-(-2r+1)+3r), so:

-(-2r+1)+3r

We add all the numbers together, and all the variables

3r-(-2r+1)

We get rid of parentheses

3r+2r-1

We add all the numbers together, and all the variables

5r-1

Back to the equation:

-(5r-1)



We add all the numbers together, and all the variables

2r-(5r-1)+14=0

We get rid of parentheses

2r-5r+1+14=0

We add all the numbers together, and all the variables

-3r+15=0

We move all terms containing r to the left, all other terms to the right

-3r=-15

r=-15/-3

r=+5

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