2(q-q)-(7q-3)+25=0

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Solution for 2(q-q)-(7q-3)+25=0 equation:


Simplifying
2(q + -1q) + -1(7q + -3) + 25 = 0

Combine like terms: q + -1q = 0
2(0) + -1(7q + -3) + 25 = 0

Multiply 2 * 0
0 + -1(7q + -3) + 25 = 0

Anything times zero is zero.
0 + -1(7q + -3) + 25 = 0

Reorder the terms:
0 + -1(-3 + 7q) + 25 = 0
0 + (-3 * -1 + 7q * -1) + 25 = 0
0 + (3 + -7q) + 25 = 0

Reorder the terms:
0 + 3 + 25 + -7q = 0

Combine like terms: 0 + 3 = 3
3 + 25 + -7q = 0

Combine like terms: 3 + 25 = 28
28 + -7q = 0

Solving
28 + -7q = 0

Solving for variable 'q'.

Move all terms containing q to the left, all other terms to the right.

Add '-28' to each side of the equation.
28 + -28 + -7q = 0 + -28

Combine like terms: 28 + -28 = 0
0 + -7q = 0 + -28
-7q = 0 + -28

Combine like terms: 0 + -28 = -28
-7q = -28

Divide each side by '-7'.
q = 4

Simplifying
q = 4

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