4(t+1)=3(t-2)

Solution for 4(t+1)=3(t-2) equation:

Simplifying
4(t + 1) = 3(t + -2)

Reorder the terms:
4(1 + t) = 3(t + -2)
(1 * 4 + t * 4) = 3(t + -2)
(4 + 4t) = 3(t + -2)

Reorder the terms:
4 + 4t = 3(-2 + t)
4 + 4t = (-2 * 3 + t * 3)
4 + 4t = (-6 + 3t)

Solving
4 + 4t = -6 + 3t

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '-3t' to each side of the equation.
4 + 4t + -3t = -6 + 3t + -3t

Combine like terms: 4t + -3t = 1t
4 + 1t = -6 + 3t + -3t

Combine like terms: 3t + -3t = 0
4 + 1t = -6 + 0
4 + 1t = -6

Add '-4' to each side of the equation.
4 + -4 + 1t = -6 + -4

Combine like terms: 4 + -4 = 0
0 + 1t = -6 + -4
1t = -6 + -4

Combine like terms: -6 + -4 = -10
1t = -10

Divide each side by '1'.
t = -10

Simplifying
t = -10