2(q-4)=3(q+2)

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Solution for 2(q-4)=3(q+2) equation:



2(q-4)=3(q+2)
We move all terms to the left:
2(q-4)-(3(q+2))=0
We multiply parentheses
2q-(3(q+2))-8=0
We calculate terms in parentheses: -(3(q+2)), so:
3(q+2)
We multiply parentheses
3q+6
Back to the equation:
-(3q+6)
We get rid of parentheses
2q-3q-6-8=0
We add all the numbers together, and all the variables
-1q-14=0
We move all terms containing q to the left, all other terms to the right
-q=14
q=14/-1
q=-14

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