X+2/3x+2/3x=233

Solution for X+2/3x+2/3x=233 equation:

X+2/3X+2/3X=233

We move all terms to the left:

X+2/3X+2/3X-(233)=0


Domain of the equation: 3X!=0

X!=0/3

X!=0

X∈R


We multiply all the terms by the denominator


X*3X-233*3X+2+2=0

We add all the numbers together, and all the variables

X*3X-233*3X+4=0

Wy multiply elements

3X^2-699X+4=0

a = 3; b = -699; c = +4;
Δ = b2-4ac
Δ = -6992-4·3·4
Δ = 488553
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-699)-\sqrt{488553}}{2*3}=\frac{699-\sqrt{488553}}{6}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-699)+\sqrt{488553}}{2*3}=\frac{699+\sqrt{488553}}{6}
$