2(n-1)+4n=(3n-1)

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Solution for 2(n-1)+4n=(3n-1) equation: 



2(n-1)+4n=(3n-1)

We move all terms to the left:

2(n-1)+4n-((3n-1))=0

We add all the numbers together, and all the variables

4n+2(n-1)-((3n-1))=0

We multiply parentheses

4n+2n-((3n-1))-2=0



We calculate terms in parentheses: -((3n-1)), so:

(3n-1)

We get rid of parentheses

3n-1

Back to the equation:

-(3n-1)



We add all the numbers together, and all the variables

6n-(3n-1)-2=0

We get rid of parentheses

6n-3n+1-2=0

We add all the numbers together, and all the variables

3n-1=0

We move all terms containing n to the left, all other terms to the right

3n=1

n=1/3

n=1/3

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