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X-5(X+3)=X+3(3-2X)
We move all terms to the left:
X-5(X+3)-(X+3(3-2X))=0
We add all the numbers together, and all the variables
X-5(X+3)-(X+3(-2X+3))=0
We multiply parentheses
X-5X-(X+3(-2X+3))-15=0
We calculate terms in parentheses: -(X+3(-2X+3)), so:We add all the numbers together, and all the variables
X+3(-2X+3)
We multiply parentheses
X-6X+9
We add all the numbers together, and all the variables
-5X+9
Back to the equation:
-(-5X+9)
-4X-(-5X+9)-15=0
We get rid of parentheses
-4X+5X-9-15=0
We add all the numbers together, and all the variables
X-24=0
We move all terms containing X to the left, all other terms to the right
X=24
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