2(n-1)+2=4(n-3)-4n

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Solution for 2(n-1)+2=4(n-3)-4n equation: 



2(n-1)+2=4(n-3)-4n

We move all terms to the left:

2(n-1)+2-(4(n-3)-4n)=0

We multiply parentheses

2n-(4(n-3)-4n)-2+2=0



We calculate terms in parentheses: -(4(n-3)-4n), so:

4(n-3)-4n

We add all the numbers together, and all the variables

-4n+4(n-3)

We multiply parentheses

-4n+4n-12

We add all the numbers together, and all the variables

-12

Back to the equation:

-(-12)



We add all the numbers together, and all the variables

2n+12=0

We move all terms containing n to the left, all other terms to the right

2n=-12

n=-12/2

n=-6

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