4n+27=5(n+4)+2

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Solution for 4n+27=5(n+4)+2 equation: 



4n+27=5(n+4)+2

We move all terms to the left:

4n+27-(5(n+4)+2)=0



We calculate terms in parentheses: -(5(n+4)+2), so:

5(n+4)+2

We multiply parentheses

5n+20+2

We add all the numbers together, and all the variables

5n+22

Back to the equation:

-(5n+22)



We get rid of parentheses

4n-5n-22+27=0

We add all the numbers together, and all the variables

-1n+5=0

We move all terms containing n to the left, all other terms to the right

-n=-5

n=-5/-1

n=+5

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