2(n+4)+3n-1=57

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Solution for 2(n+4)+3n-1=57 equation: 



2(n+4)+3n-1=57

We move all terms to the left:

2(n+4)+3n-1-(57)=0

We add all the numbers together, and all the variables

3n+2(n+4)-58=0

We multiply parentheses

3n+2n+8-58=0

We add all the numbers together, and all the variables

5n-50=0

We move all terms containing n to the left, all other terms to the right

5n=50

n=50/5

n=10

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