2(n+3)+3(2n-5)=4n+15

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Solution for 2(n+3)+3(2n-5)=4n+15 equation: 



2(n+3)+3(2n-5)=4n+15

We move all terms to the left:

2(n+3)+3(2n-5)-(4n+15)=0

We multiply parentheses

2n+6n-(4n+15)+6-15=0

We get rid of parentheses

2n+6n-4n-15+6-15=0

We add all the numbers together, and all the variables

4n-24=0

We move all terms containing n to the left, all other terms to the right

4n=24

n=24/4

n=6

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