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-6n(3n-4)=0
We multiply parentheses
-18n^2+24n=0
a = -18; b = 24; c = 0;
Δ = b2-4ac
Δ = 242-4·(-18)·0
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{576}=24$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-24}{2*-18}=\frac{-48}{-36} =1+1/3 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+24}{2*-18}=\frac{0}{-36} =0 $
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