2(n+2)=-10+n-(6n-21)

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Solution for 2(n+2)=-10+n-(6n-21) equation: 



2(n+2)=-10+n-(6n-21)

We move all terms to the left:

2(n+2)-(-10+n-(6n-21))=0

We multiply parentheses

2n-(-10+n-(6n-21))+4=0



We calculate terms in parentheses: -(-10+n-(6n-21)), so:

-10+n-(6n-21)

determiningTheFunctionDomain
n-(6n-21)-10

We get rid of parentheses

n-6n+21-10

We add all the numbers together, and all the variables

-5n+11

Back to the equation:

-(-5n+11)



We get rid of parentheses

2n+5n-11+4=0

We add all the numbers together, and all the variables

7n-7=0

We move all terms containing n to the left, all other terms to the right

7n=7

n=7/7

n=1

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