2(n+12)=3/2(2n+12

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Solution for 2(n+12)=3/2(2n+12 equation: 



2(n+12)=3/2(2n+12

We move all terms to the left:

2(n+12)-(3/2(2n+12)=0



Domain of the equation: 2(2n+12)!=0

n∈R



We multiply parentheses

2n-(3/2(2n+12)+24=0

We multiply all the terms by the denominator


2n*2(2n+12)+24-(3=0

We add all the numbers together, and all the variables

2n*2(2n+12)=0

Wy multiply elements

4n^2(2=0

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