3r+3=2(5+r)

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Solution for 3r+3=2(5+r) equation: 



3r+3=2(5+r)

We move all terms to the left:

3r+3-(2(5+r))=0

We add all the numbers together, and all the variables

3r-(2(r+5))+3=0



We calculate terms in parentheses: -(2(r+5)), so:

2(r+5)

We multiply parentheses

2r+10

Back to the equation:

-(2r+10)



We get rid of parentheses

3r-2r-10+3=0

We add all the numbers together, and all the variables

r-7=0

We move all terms containing r to the left, all other terms to the right

r=7

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