2(m-5)=-22+4m

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Solution for 2(m-5)=-22+4m equation:



2(m-5)=-22+4m
We move all terms to the left:
2(m-5)-(-22+4m)=0
We add all the numbers together, and all the variables
2(m-5)-(4m-22)=0
We multiply parentheses
2m-(4m-22)-10=0
We get rid of parentheses
2m-4m+22-10=0
We add all the numbers together, and all the variables
-2m+12=0
We move all terms containing m to the left, all other terms to the right
-2m=-12
m=-12/-2
m=+6

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