-6(u+1)+8u=2((u-3)

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Solution for -6(u+1)+8u=2((u-3) equation: 



-6(u+1)+8u=2((u-3)

We move all terms to the left:

-6(u+1)+8u-(2((u-3))=0

We add all the numbers together, and all the variables

8u-6(u+1)-(2((u-3))=0

We multiply parentheses

8u-6u-(2((u-3))-6=0

We add all the numbers together, and all the variables

2u-(2((u-3))-6=0

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