2(m+50)+50=3(m-30)+50-70

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Solution for 2(m+50)+50=3(m-30)+50-70 equation: 



2(m+50)+50=3(m-30)+50-70

We move all terms to the left:

2(m+50)+50-(3(m-30)+50-70)=0

We multiply parentheses

2m-(3(m-30)+50-70)+100+50=0



We calculate terms in parentheses: -(3(m-30)+50-70), so:

3(m-30)+50-70

We add all the numbers together, and all the variables

3(m-30)-20

We multiply parentheses

3m-90-20

We add all the numbers together, and all the variables

3m-110

Back to the equation:

-(3m-110)



We add all the numbers together, and all the variables

2m-(3m-110)+150=0

We get rid of parentheses

2m-3m+110+150=0

We add all the numbers together, and all the variables

-1m+260=0

We move all terms containing m to the left, all other terms to the right

-m=-260

m=-260/-1

m=+260

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