5(2x-4)=2(-x+5)+2(3x-4)

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Solution for 5(2x-4)=2(-x+5)+2(3x-4) equation: 



5(2x-4)=2(-x+5)+2(3x-4)

We move all terms to the left:

5(2x-4)-(2(-x+5)+2(3x-4))=0

We add all the numbers together, and all the variables

5(2x-4)-(2(-1x+5)+2(3x-4))=0

We multiply parentheses

10x-(2(-1x+5)+2(3x-4))-20=0



We calculate terms in parentheses: -(2(-1x+5)+2(3x-4)), so:

2(-1x+5)+2(3x-4)

We multiply parentheses

-2x+6x+10-8

We add all the numbers together, and all the variables

4x+2

Back to the equation:

-(4x+2)



We get rid of parentheses

10x-4x-2-20=0

We add all the numbers together, and all the variables

6x-22=0

We move all terms containing x to the left, all other terms to the right

6x=22

x=22/6

x=3+2/3

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