2(m+10)=4(m-15)+20

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Solution for 2(m+10)=4(m-15)+20 equation:



2(m+10)=4(m-15)+20
We move all terms to the left:
2(m+10)-(4(m-15)+20)=0
We multiply parentheses
2m-(4(m-15)+20)+20=0
We calculate terms in parentheses: -(4(m-15)+20), so:
4(m-15)+20
We multiply parentheses
4m-60+20
We add all the numbers together, and all the variables
4m-40
Back to the equation:
-(4m-40)
We get rid of parentheses
2m-4m+40+20=0
We add all the numbers together, and all the variables
-2m+60=0
We move all terms containing m to the left, all other terms to the right
-2m=-60
m=-60/-2
m=+30

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