4(2c+12)+c=3

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Solution for 4(2c+12)+c=3 equation: 



4(2c+12)+c=3

We move all terms to the left:

4(2c+12)+c-(3)=0

We add all the numbers together, and all the variables

c+4(2c+12)-3=0

We multiply parentheses

c+8c+48-3=0

We add all the numbers together, and all the variables

9c+45=0

We move all terms containing c to the left, all other terms to the right

9c=-45

c=-45/9

c=-5

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