2(k-4)-(1-3k)=k+5+3k-1

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Solution for 2(k-4)-(1-3k)=k+5+3k-1 equation: 



2(k-4)-(1-3k)=k+5+3k-1

We move all terms to the left:

2(k-4)-(1-3k)-(k+5+3k-1)=0

We add all the numbers together, and all the variables

2(k-4)-(-3k+1)-(4k+4)=0

We multiply parentheses

2k-(-3k+1)-(4k+4)-8=0

We get rid of parentheses

2k+3k-4k-1-4-8=0

We add all the numbers together, and all the variables

k-13=0

We move all terms containing k to the left, all other terms to the right

k=13

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