2(k-3)-4=28-k

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Solution for 2(k-3)-4=28-k equation: 



2(k-3)-4=28-k

We move all terms to the left:

2(k-3)-4-(28-k)=0

We add all the numbers together, and all the variables

2(k-3)-(-1k+28)-4=0

We multiply parentheses

2k-(-1k+28)-6-4=0

We get rid of parentheses

2k+1k-28-6-4=0

We add all the numbers together, and all the variables

3k-38=0

We move all terms containing k to the left, all other terms to the right

3k=38

k=38/3

k=12+2/3

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