(10x+3)=(8x+19)=

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Solution for (10x+3)=(8x+19)= equation: 



(10x+3)=(8x+19)=

We move all terms to the left:

(10x+3)-((8x+19))=0

We get rid of parentheses

10x-((8x+19))+3=0



We calculate terms in parentheses: -((8x+19)), so:

(8x+19)

We get rid of parentheses

8x+19

Back to the equation:

-(8x+19)



We get rid of parentheses

10x-8x-19+3=0

We add all the numbers together, and all the variables

2x-16=0

We move all terms containing x to the left, all other terms to the right

2x=16

x=16/2

x=8

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