2(k-1)+3(k+4)=7k+4

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Solution for 2(k-1)+3(k+4)=7k+4 equation: 



2(k-1)+3(k+4)=7k+4

We move all terms to the left:

2(k-1)+3(k+4)-(7k+4)=0

We multiply parentheses

2k+3k-(7k+4)-2+12=0

We get rid of parentheses

2k+3k-7k-4-2+12=0

We add all the numbers together, and all the variables

-2k+6=0

We move all terms containing k to the left, all other terms to the right

-2k=-6

k=-6/-2

k=+3

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