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2(k+3)=5(3+k)=5k-5k
We move all terms to the left:
2(k+3)-(5(3+k))=0
We add all the numbers together, and all the variables
2(k+3)-(5(k+3))=0
We multiply parentheses
2k-(5(k+3))+6=0
We calculate terms in parentheses: -(5(k+3)), so:We get rid of parentheses
5(k+3)
We multiply parentheses
5k+15
Back to the equation:
-(5k+15)
2k-5k-15+6=0
We add all the numbers together, and all the variables
-3k-9=0
We move all terms containing k to the left, all other terms to the right
-3k=9
k=9/-3
k=-3
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