((10x-3)/10)-((3x+3)/3)=1/10

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Solution for ((10x-3)/10)-((3x+3)/3)=1/10 equation: 



((10x-3)/10)-((3x+3)/3)=1/10

We move all terms to the left:

((10x-3)/10)-((3x+3)/3)-(1/10)=0

We add all the numbers together, and all the variables

((10x-3)/10)-((3x+3)/3)-(+1/10)=0

We get rid of parentheses

((10x-3)/10)-((3x+3)/3)-1/10=0

We calculate fractions


(30x-9)/()+(-((3x+3)*10)*10)/()+()/()=0



We calculate terms in parentheses: +(-((3x+3)*10)*10)/(), so:

-((3x+3)*10)*10)/(

We multiply all the terms by the denominator


-((3x+3)*10)*10)



We calculate terms in parentheses: -((3x+3)*10)*10), so:

(3x+3)*10)*10

We multiply parentheses

30x+

We add all the numbers together, and all the variables

30x

Back to the equation:

-(30x)



Back to the equation:

+(-30x)



We add all the numbers together, and all the variables

(30x-9)/()+(-30x)+1=0

We get rid of parentheses

(30x-9)/()-30x+1=0

We multiply all the terms by the denominator


(30x-9)-30x*()+1*()=0

We add all the numbers together, and all the variables

(30x-9)-30x*()=0

We get rid of parentheses

30x-30x*()-9=0

We move all terms containing x to the left, all other terms to the right

30x-30x*()=9

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