2(k+2)=4(k-5)

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Solution for 2(k+2)=4(k-5) equation: 



2(k+2)=4(k-5)

We move all terms to the left:

2(k+2)-(4(k-5))=0

We multiply parentheses

2k-(4(k-5))+4=0



We calculate terms in parentheses: -(4(k-5)), so:

4(k-5)

We multiply parentheses

4k-20

Back to the equation:

-(4k-20)



We get rid of parentheses

2k-4k+20+4=0

We add all the numbers together, and all the variables

-2k+24=0

We move all terms containing k to the left, all other terms to the right

-2k=-24

k=-24/-2

k=+12

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