1(-2/3)v=3

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Solution for 1(-2/3)v=3 equation:



1(-2/3)v=3
We move all terms to the left:
1(-2/3)v-(3)=0
Domain of the equation: 3)v!=0
v!=0/1
v!=0
v∈R
We multiply parentheses
-2v^2-3=0
a = -2; b = 0; c = -3;
Δ = b2-4ac
Δ = 02-4·(-2)·(-3)
Δ = -24
Delta is less than zero, so there is no solution for the equation

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