2(k+2)+3k=2(k+1)+1

Solution for 2(k+2)+3k=2(k+1)+1 equation:

2(k+2)+3k=2(k+1)+1

We move all terms to the left:

2(k+2)+3k-(2(k+1)+1)=0

We add all the numbers together, and all the variables

3k+2(k+2)-(2(k+1)+1)=0

We multiply parentheses

3k+2k-(2(k+1)+1)+4=0


We calculate terms in parentheses: -(2(k+1)+1), so:

2(k+1)+1

We multiply parentheses

2k+2+1

We add all the numbers together, and all the variables

2k+3

Back to the equation:

-(2k+3)


We add all the numbers together, and all the variables

5k-(2k+3)+4=0

We get rid of parentheses

5k-2k-3+4=0

We add all the numbers together, and all the variables

3k+1=0

We move all terms containing k to the left, all other terms to the right

3k=-1

k=-1/3

k=-1/3