4(v-2)-6=-6(-4v+1)-4v

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Solution for 4(v-2)-6=-6(-4v+1)-4v equation: 



4(v-2)-6=-6(-4v+1)-4v

We move all terms to the left:

4(v-2)-6-(-6(-4v+1)-4v)=0

We multiply parentheses

4v-(-6(-4v+1)-4v)-8-6=0



We calculate terms in parentheses: -(-6(-4v+1)-4v), so:

-6(-4v+1)-4v

We add all the numbers together, and all the variables

-4v-6(-4v+1)

We multiply parentheses

-4v+24v-6

We add all the numbers together, and all the variables

20v-6

Back to the equation:

-(20v-6)



We add all the numbers together, and all the variables

4v-(20v-6)-14=0

We get rid of parentheses

4v-20v+6-14=0

We add all the numbers together, and all the variables

-16v-8=0

We move all terms containing v to the left, all other terms to the right

-16v=8

v=8/-16

v=-1/2

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