2(j-3)+7=-7

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Solution for 2(j-3)+7=-7 equation: 



2(j-3)+7=-7

We move all terms to the left:

2(j-3)+7-(-7)=0

We add all the numbers together, and all the variables

2(j-3)+14=0

We multiply parentheses

2j-6+14=0

We add all the numbers together, and all the variables

2j+8=0

We move all terms containing j to the left, all other terms to the right

2j=-8

j=-8/2

j=-4

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