123=(2n-9)+(3n+6)+n

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Solution for 123=(2n-9)+(3n+6)+n equation: 



123=(2n-9)+(3n+6)+n

We move all terms to the left:

123-((2n-9)+(3n+6)+n)=0



We calculate terms in parentheses: -((2n-9)+(3n+6)+n), so:

(2n-9)+(3n+6)+n

We add all the numbers together, and all the variables

n+(2n-9)+(3n+6)

We get rid of parentheses

n+2n+3n-9+6

We add all the numbers together, and all the variables

6n-3

Back to the equation:

-(6n-3)



We get rid of parentheses

-6n+3+123=0

We add all the numbers together, and all the variables

-6n+126=0

We move all terms containing n to the left, all other terms to the right

-6n=-126

n=-126/-6

n=+21

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