2(f+2)=+5(f+4)

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Solution for 2(f+2)=+5(f+4) equation: 



2(f+2)=+5(f+4)

We move all terms to the left:

2(f+2)-(+5(f+4))=0

We multiply parentheses

2f-(+5(f+4))+4=0



We calculate terms in parentheses: -(+5(f+4)), so:

+5(f+4)

determiningTheFunctionDomain
5(f+4)

We multiply parentheses

5f+20

Back to the equation:

-(5f+20)



We get rid of parentheses

2f-5f-20+4=0

We add all the numbers together, and all the variables

-3f-16=0

We move all terms containing f to the left, all other terms to the right

-3f=16

f=16/-3

f=-5+1/3

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