2(d-4)=6(d+2)

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Solution for 2(d-4)=6(d+2) equation: 



2(d-4)=6(d+2)

We move all terms to the left:

2(d-4)-(6(d+2))=0

We multiply parentheses

2d-(6(d+2))-8=0



We calculate terms in parentheses: -(6(d+2)), so:

6(d+2)

We multiply parentheses

6d+12

Back to the equation:

-(6d+12)



We get rid of parentheses

2d-6d-12-8=0

We add all the numbers together, and all the variables

-4d-20=0

We move all terms containing d to the left, all other terms to the right

-4d=20

d=20/-4

d=-5

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