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3(x-1)=6(x+2)
We move all terms to the left:
3(x-1)-(6(x+2))=0
We multiply parentheses
3x-(6(x+2))-3=0
We calculate terms in parentheses: -(6(x+2)), so:We get rid of parentheses
6(x+2)
We multiply parentheses
6x+12
Back to the equation:
-(6x+12)
3x-6x-12-3=0
We add all the numbers together, and all the variables
-3x-15=0
We move all terms containing x to the left, all other terms to the right
-3x=15
x=15/-3
x=-5
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