2(c-6)+3c=10-6c

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Solution for 2(c-6)+3c=10-6c equation: 



2(c-6)+3c=10-6c

We move all terms to the left:

2(c-6)+3c-(10-6c)=0

We add all the numbers together, and all the variables

2(c-6)+3c-(-6c+10)=0

We add all the numbers together, and all the variables

3c+2(c-6)-(-6c+10)=0

We multiply parentheses

3c+2c-(-6c+10)-12=0

We get rid of parentheses

3c+2c+6c-10-12=0

We add all the numbers together, and all the variables

11c-22=0

We move all terms containing c to the left, all other terms to the right

11c=22

c=22/11

c=2

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